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Re: Wattmeter
T
> Terry, Steve, ALL
>
> Sorry about the miscommunication.. :^C
>
>
> 1. Wind a 50:1 current transformer (CT) on ferrite core. Pass
> main power path =insulated= conductor through opening with
> additional polyethylene tubing insulation. This will feed
> a shunt of approximately 12 milliohms.
Why not use one of those Honeywell hall effect current sensors? They
have fairly good bandwidth, a hole through the middle for your wire, and
produce a buffered analog output. Saves winding coils and toroids, etc.
They were about $20 last time I checked..
--
Jim Lux Jet Propulsion Laboratory
ofc: 818/354-2075 114-B16 Mail Stop 161-213
lab: 818/354-2954 161-110 4800 Oak Grove Drive
fax: 818/393-6875 Pasadena CA 91109