Re: RMS (Re: Why do primaries get hot?)

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "rheidlebaugh by way of Terry Fritz <twftesla-at-qwest-dot-net>" <rheidlebaugh-at-zialink-dot-com>

Just a side note: Tesla ( US Patt 685,012) points out that primary heating
is a major problem causing de-tuning of the TC circuit.
   Robert  H

> From: "Tesla list" <tesla-at-pupman-dot-com>
> Date: Fri, 01 Mar 2002 21:58:38 -0700
> To: tesla-at-pupman-dot-com
> Subject: Re: RMS   (Re: Why do primaries get hot?)
> Resent-From: tesla-at-pupman-dot-com
> Resent-Date: Fri, 1 Mar 2002 22:14:44 -0700
> 
> Original poster: "Jim Lux by way of Terry Fritz <twftesla-at-qwest-dot-net>"
> <jimlux-at-earthlink-dot-net>
> 
>> 
>>> say, 0.01 uF,253 uH (100 kHz)  pk current is around 100 Amps..
>>> Assume loaded Q is around 2, so current falls off to 37 Amps in 2 cycles,
>>> or 20 microseconds.  Assume we do this every 8 milliseconds (each half
>>> cycle, rounding to make math easier).. The duty cycle is roughly, then,
>>> 20/8000 or 1/400.
>> 
>> Concur, sort of.
>> I suggest that the use of 'duty cycle' can be iffy EXCEPT in
>> pure pulse systems.  With resonant systems (all TC are, more or
>> less) the quasi sinusoidal waveforms are EVERY where.
>> 
>> (A nice, computing scope, capable of doing Real Power on the
>> fly, or true RMS reading ammeter & voltmeter & power factor
>> set up...)
>> 
> 
> Exactly... but, to a rough order of magnitude, it's correct.. Figuring
> total energy in the whole "bang" would be comparable to a rectangular pulse
> lasting 2 cycles...
> 
> 
>