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RE: Mutual Inductance & K Factor (was : Arc Over Between Secondary and Primary Coils)
Original poster: "John H. Couture by way of Terry Fritz <twftesla-at-qwest-dot-net>" <couturejh-at-mgte-dot-com>
Bart, Nolan -
I goofed, sorry. Ignore my other posts, I was using Ls = 93.79 instead of
9.379 mh.
For Nolan's coil I get the following with the JHCTES Ver 3.3 program.
Secondary 1.19 - 867 - 68 - 0 - 10
Primary .03 - 3.30 - 0 - 1.4
Outputs Fr = 470.91 Khz Lm = 33.24 uh K = .194
Lp = 3.81 uh Ls = 7.7 mh
Pri turns = 3.82
Sec turns = 68 TPI x 12.75 Lgt = 867
Pri/Sec clearance = 1.41 inches
Pri inside rad = 2.6
Pri c/c turns = .37
With Sec above Pri = 3
Lm = 14.16 uh K = .083
It will be interesting to find the true mutual inductances and K Factors if
Nolan tests his coil for these two parameters.
John Couture
---------------------------
-----Original Message-----
From: Tesla list [mailto:tesla-at-pupman-dot-com]
Sent: Saturday, March 16, 2002 12:07 PM
To: tesla-at-pupman-dot-com
Subject: Re: Arc Over Between Secondary and Primary Coils
Original poster: "Barton B. Anderson by way of Terry Fritz
<twftesla-at-qwest-dot-net>" <tesla123-at-pacbell-dot-net>
Hi John, Paul, Nolan,
Nolan, hope you don't mind if we play around with the numbers. Also, can
you verify something. Is your
secondary 15" high wound with 28 awg with a winding length of 12.75"? If
so, I used 15" previous, so
all the numbers will be off, but it's a good exersize anyway.
John, on the helix -3.000 value, I used a wrong input. However, I see what
your getting at.
Paul, Acmi appears to not equate correctly using Acmi's own inductances and
K. I think John is correct
here. I will go back and check my inputs to see if I made some error. Maybe
you can take a look at the
input file I sent.
I'm pretty sure Nolan's secondary is 12.75" high and not 15". I'll go back
through these today with
this new secondary length. If you can check with the 15" length anyway, I
think all the other inputs
were correct.
Take Care,
Bart