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Re: rectifier stack experts?
Original poster: "Malcolm Watts by way of Terry Fritz <twftesla-at-qwest-dot-net>" <m.j.watts-at-massey.ac.nz>
On 22 Oct 2002, at 18:44, Tesla list wrote:
> Original poster: "Craig Fuller by way of Terry Fritz
<twftesla-at-qwest-dot-net>" <cbfull-at-hotmail-dot-com>
>
> Jim,
>
> I am not trying to be confrontational, but I don't think your statement is
> correct. Maybe you can clarify what you mean, in case I misunderstood you.
>
> The way I see it, if you draw out a full bridge, each diode in the bridge
> being rated accordingly for 1 volt (with a small margin for error, so say
> 1.1 volts) and create a scenario where the cap is fully charged to 1 volt,
> and the AC signal is at a peak value (which is also +1 and -1, or vise
> versa) each diode potentially sees +2 or -2 volts as a maximum, and
> breakdown will occur.
What do you mean by "potentially"? Consider one half cycle and
replace each conducting diode by a piece of wire in your diagram.
What you actually get is two reverse-biased diodes in parallel across
the transformer/capacitor which are also essentially in parallel. In
a f.w. bridge configuration, Vtransformer and Vcapacitor never appear
added in series across anything. Very different from centre-tapped
f.w. or voltage-doubling half wave configurations I might add.
Regards,
Malcolm
The only place where you are protected by 2 diodes in
> series, is across the capacitor terminals, which also appears at the + and -
> terminals of the bridge. This is not where the problem occurs. The problem
> occurs between a polarized terminal and a non-polarized terminal of the
> bridge. Am I making any sense, or do I have this all wrong?
>
> Craig
>
>
>
>
>
> >Original poster: "Jim Lux by way of Terry Fritz <twftesla-at-qwest-dot-net>"
> ><jimlux-at-earthlink-dot-net>
> >
> >Think of it when the output of the transformer is opposite in polarity from
> >that on the capacitor.. 2*Vpeak..
> >
> >Bear in mind, though, that if you are using a bridge rectifier, you have
> >two diodes in series, so each diode really only needs to be rated for Vpeak
> >(plus margin!).
>
>
>
>