RE: capacitance formula

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "Lau, Gary by way of Terry Fritz <teslalist-at-qwest-dot-net>" <Gary.Lau-at-hp-dot-com>

If I may whine about one of my peeves - Referring to the resistors as 
"equalizing" perpetuates the misunderstanding that they determine the 
voltage division between series-ed caps.  The resistors are far higher 
impedance than the reactance of the caps at 60 Hz and have no bearing on 
the voltage division.  They are strictly for bleeding off charges that 
accumulate asymmetrically on series caps, for reasons that frankly, are not 
understood.  They should be referred to as bleeder resistors.

Gary Lau
MA, USA

 >Original poster: "by way of Terry Fritz 
<teslalist-at-qwest-dot-net>" ><dhmccauley-at-spacecatlighting-dot-com>
 >
 >Theoretically yes, in reality no.  You can never assume capacitors in series
 >will share voltage equally among them.
 >In practice,  you would also use equalizing resistors across each capacitor
 >to equalize the voltage across the capacitors.
 >
 >The Captain