Re: Triac as gap replacement

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: "June Heidlebaugh by way of Terry Fritz <teslalist-at-qwest-dot-net>" <rheidlebaugh-at-desertgate-dot-com>

a solid state relay us just a diode bridge with a SCR shorting across the DC
output points of the bridge. This would act as a AC with with no problems
with inductive kick back
-        Robert  H---- Original Message -----
From: Tesla list <tesla-at-pupman-dot-com>
To: <tesla-at-pupman-dot-com>
Sent: Thursday, June 19, 2003 8:08 AM
Subject: Re: Triac as gap replacement


 > Original poster: "Richard W. by way of Terry Fritz <teslalist-at-qwest-dot-net>"
<potluck-at-xmission-dot-com>
 >
 > Hi Ken,
 > I've done a lot of cramming about triacs and SCRs lately. So much so that
a
 > lot has seemed to run together. Anyway, as far as current capability the
 > back-to-back SCR is the way to go as far as I understand. There's
something
 > about current lag in inductive circuits that won't allow a triac to turn
off
 > or something like that. I would assume a capacitive load would be just as
 > bad. The word "commutate" comes to mind somewhere. With back-to-back SCRs
 > each SCR will always turn off every other cycle due to it's inherent
 > properties.
 >
 > Maybe someone else here can clarify that for you.
 >
 > Rick W.
 > Salt Lake City
 >
 > ----- Original Message -----
 > From: Tesla list <tesla-at-pupman-dot-com>
 > To: <tesla-at-pupman-dot-com>
 > Sent: Wednesday, June 18, 2003 8:12 PM
 > Subject: Triac as gap replacement
 >
 >
 >  > Original poster: "K. C. Herrick by way of Terry Fritz
 > <teslalist-at-qwest-dot-net>" <kchdlh-at-juno-dot-com>
 >  >
 >  > Have any of you looked into triacs having something like these
 >  > capabilities?
 >  >
 >  > Voltage withstanding, 600 V
 >  >
 >  > Current capability, sine-ac bursts of 3 KA peak declining over 10
cycles
 >  > to 10% in 100 us, and repeated -at- 120 bps.  In the circuit I'm
 >  > contemplating, that seems to be about 20 A rms (which is the
 >  > charging-current into the primary capacitors; I figure, rms current in
=
 >  > rms current out).
 >  >
 >  > If so, can you save me some looking?
 >  >
 >  > Ken Herrick
 >  >
 >  >
 >  >
 >
 >