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Re: Best secondary size
Original poster: "Dr. Resonance" <resonance-at-jvlnet-dot-com>
I agree with your assessment. I was essentially using the k value as a
coeff. of efficiency which multiplied times the Vin x sqr Ls/Lp would give a
value for approx. output.
It could also be incorporated, as you correctly pointed out, in other
equations related to the Fs and Fp values, ie, Fsec = Fpri.
Dr. Resonance
>
> You and Malcolm are right. I get the feeling sometimes coupling and
efficiency are being
> confused in these discussions.
>
> The coupling between prim. and sec. coil, k, is defined by
>
> k = M/SQRT(Lp*Ls) (1)
>
> M being the mutual inductance of prim. and sec. coil.
>
> The efficiency, eps, of the system expresses how much of the primary
> energy (e.g. in C1) will *eventually* end up in C2:
>
> Es = eps*Ep (2)
>
> There is not really a direct link between k and eps, but there *is* a
> link between how many oscillations it takes to transfer the total
> primary energy, Ep, to C2 and k. The smaller k, the longer it takes
> for Ep to end up at C2.
> In [1] the following approximate expression is given for this transfer
> time tau
>
> tau = (1/(2*f_res))*SQRT(1-k^2)/k (3)
>
> so if k = 0.15 -> tau = (1/(2*f_res))*6.6
> if k = 0.3 -> tau = (1/(2*f_res))*3.2
>
> in case k = 0.15 it takes 6.6 half oscillations for Ep to arrive at C2;
> in the ideal case then the spark gap will quench, so the energy
> stays in the secundary circuit and will exponentially decay.
>
> Since Ep = 0.5*Cp*Vp^2, and the same for Es, one gets from (2)
>
> Vs = Vp*SQRT(eps*Cp/Cs) (4)
>
> or, expressed in inductances,
>
> Vs = Vp*SQRT(eps*Ls/Lp) (5)
>
> k does not occur in (4) and (5)
>
> ------------------
> [1] - Kenneth D. Skeldon, Alastair I. Grant and Slan A. Scott, "A high
> potential
> Tesla coil impulse generator for lecture demonstrations and science
> exhibitions",
> Am. J. Phys. 65(8), 744-754 (1997)
>
>
>
> hope this is helpful, Rob Maas
>
>
>