Re: Turns to secondary length ratio...

["Tesla list" <tesla-at-pupman-dot-com>]

Original poster: Esondrmn-at-aol-dot-com 

In a message dated 1/30/04 6:19:26 PM Pacific Standard Time, 
tesla-at-pupman-dot-com writes:

Well, you said that you wanted 1200 turns.  #22 heavy build wire is about 
35.6 turns per inch so 1200 turns would require a winding length of 33.7 
inches.  This would make a very tall, skinny coil, which is not the best 
for performance.  #22 wire would work fine for say a six inch diameter form.

Ed Sonderman

>Ic, so I am guessing #22 gauge is too big for a 3 inch coil?
>
>---Eric Urban
>----- Original Message -----
>From: "Tesla list" <tesla-at-pupman-dot-com>
>To: <tesla-at-pupman-dot-com>
>Sent: Friday, January 30, 2004 1:06 PM
>Subject: Re: Turns to secondary length ratio...
>
>
> > Original poster: Esondrmn-at-aol-dot-com
> >
> > In a message dated 1/29/04 5:28:49 PM Pacific Standard Time,
> > tesla-at-pupman-dot-com writes:
> >
> >
> > >Original poster: "Hydrogen18" <hydrogen18-at-hydrogen18-dot-com>
> > >
> > >How long should a 3 inch secondary be for 1200 turns?
> >
> >
> > Hydrogen,
> >
> > Well, if you wanted say a 5 :1 ratio of winding length to width, you would
> > need to use a wire that is about .0125 diameter which is approximately #
> > 29.5 guage.  So, using # 30 heavy build wire, diameter .0119" would give
>us
> > a turns per inch of 84.  Assuming a winding density of 95% we get 79.8
> > turns per inch.  Times 15 inches we would have 1,197 turns.
> >
> > Ed Sonderman