Re[2]: Capacitor Help

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Original poster: Illicium Verum <sebas@xxxxxxxxxxxxxxxx>


Hello Dennis,

You just use combine different values.

Let me give you an example :)

Assuming your transformer peak voltage is 21213.2034355964 volt

A primary capacitor should be rated higher lets say: 26516.5042944955 volt


If your capacitor specifications are;

450VAC

1000VDC

An assuming you would like to use the AC rating, this would require 
59 caps per string.

That means if you would like to have a 20nF primary capacitor and you 
would like to have 2 strings you could buy and place in series;

51 x 680nF + 8 x 15nF

this will give you a capacitance of 19.9942545245619nF


for 3 strings you would need;

49 x 470nF + 10 x 15nF

this will give you a capacitance of 19.9770180982476nF



But is you only use DC rating you would need 27 caps per string

And again for 2 strings

22 x 330nF + 5 x 6.8nF

this will give you a capacitance of 20.0109739368999nF


for 3 strings you would need;

22 x 220nF + 5 x 6.8nF

this will give you a capacitance of 20.0576131687243nF


Kind regards,

Sebastiaan


Saturday, December 17, 2005, 5:39:25 AM, you wrote:


> Original poster: <mailto:otmaskin5@xxxxxxx>otmaskin5@xxxxxxx


> A question on this...


> Terry, you mention CD 942   0.15 uF caps.  If you only need to match

> 0.02 uF, will the proper MMC array actually retuce total capacitance

> using these caps so you're not dramatically LTR?  If so, what's the

> principle that reduces total capacitance when individual caps are

> higher?  Thanks.  Dennis Hopkintom, MA