Re: Resistors For Terry Filter

["Tesla list" <tesla@xxxxxxxxxx>]

Original poster: "Bob (R.A.) Jones" <a1accounting@xxxxxxxxxxxxx>

Hi,

Actually they see the full main cap voltage when the SG fires but only for 
the time it takes to discharge the filter caps.

Specifically the dissipation can be separated in to two components.
1. The dissipation caused by low frequency (break rate) charging current, 
that's your 30mA.
2. The transient dissipation caused by the discharge current of the filter 
caps.
Approximately given by 1/2*C*V^2*(break rate) where C is the filter cap 
value, V is the break down voltage of the SG.



> Original poster: "Daniel Koll" <dk_spl_audio@xxxxxxxxxxx>
>
> Yeah, Terry explained that too.  I forgot that they only see the voltage 
> that they drop (duh!)  Thanks!
>
> > From: "Tesla list" <tesla@xxxxxxxxxx>
> > To: tesla@xxxxxxxxxx
> > Subject: RE: Resistors For Terry Filter
> > Date: Fri, 06 May 2005 12:21:39 -0600
> >
> > Original poster: "Ian McLean" <ianmm@xxxxxxxxxxxxxxx>
> >
> > Hi Daniel,
> >
> > This question pops up from time to time on the list.  I thought I might have
> > a crack at answering this one for you.
> >
> > Basically, you have the resistors in series with the high voltage outputs so
> > they are effectively floating at 6kV.  All they "see" is the voltage drop
> > across the resistor according to ohms law - in this case 1kR x whatever
> > current rating your transformer is at. For example V=IR so for a 30mA 
> > transformer that would be 1kR x 30mA = 30V assuming your
> > using the 1K resistors as in the Terry Filter.
> >
> > Anyway you can see that the resistors are not stressed by the potential
> > difference across them.  As long as the resistors are long enough to prevent
> > arcs across them then your pretty much OK.

Robert (R. A.) Jones
A1 Accounting, Inc., Fl
407 649 6400