RE: peak current when spark gap fires

["Tesla list" <tesla@xxxxxxxxxx>]

Original poster: Vardan <vardan01@xxxxxxxxxxxxxxxxxxxxxxx>

Hi,

This page explains the SQRT(2) factor and how it is found:

http://www.ee.unb.ca/tervo/ee2791/vrms.htm

Cheers,

        Terry


At 10:27 PM 10/20/2006, you wrote:
> Say was does the SQR of 2 come from. It easy to imagine .707 * peak or
> rms/.707 hmm Root Means square...to the Inet. Never mind the math gets out
> there for a "collection of n".
>
> Elementary but I don't remember covering it that way.
>
> -----Original Message-----
> From: Tesla list [mailto:tesla@xxxxxxxxxx]
> Sent: Friday, October 20, 2006 6:10 PM
> To: tesla@xxxxxxxxxx
> Subject: Re: peak current when spark gap fires
>
> Original poster: Vardan <vardan01@xxxxxxxxxxxxxxxxxxxxxxx>
>
> Hi,
>
> There is a list of such formulas here:
>
> http://hot-streamer.com/temp/FormulasForTeslaCoils.pdf
>
> The formula you want is at the top of page 6.
>
> However, you already figured it out almost correctly ;-)  The thing I
> would change is the actual voltage the gap fires at.  If your NST is
> rated at 12000V RMS then the peak voltage will be 12000 x SQRT(2) =
> 16970 V.  So the primary peak current is probably 245 amps.
>
> Cheers,
>
>          Terry
>
>
> At 09:23 PM 10/19/2006, you wrote:
> >Hello. I am new to a lot of this, so I want to make sure I got this
> >correct. Did I do this right to find the peak current when the spark
> >gap fires? Assuming the only inductance in the calculation is the
> >primary coil....
> >
> >Surge impedance = sqrt(Lp / Cp)      my primary is around 48.029uH
> >according to calculations, and capacitor is
> >0.01uF    so  sqrt(0.000048 / 0.00000001F) = 69.282     and then
> >current peak = Vp / Surge impedance  so  12000 / 69.282   = 173.205
> >amps?   This is most likely way wrong :P