RE: double wound secondary (fwd)

["Tesla list" <tesla@xxxxxxxxxx>]

---------- Forwarded message ----------
Date: Mon, 1 Oct 2007 10:06:33 -0400
From: Scott Bogard <teslas-intern@xxxxxxxxxxx>
To: Tesla list <tesla@xxxxxxxxxx>
Subject: RE: double wound secondary (fwd)


Thanks guys, 
     I understand much better now.
Scott Bogard.

> Date: Sun, 30 Sep 2007 08:35:57 -0600
> From: tesla@xxxxxxxxxx
> To: tesla@xxxxxxxxxx
> Subject: Re: double wound secondary (fwd)
> 
> 
> ---------- Forwarded message ----------
> Date: Sun, 30 Sep 2007 11:06:50 -0300
> From: Antonio Carlos M. de Queiroz <acmdq@xxxxxxxxxx>
> To: Tesla list <tesla@xxxxxxxxxx>
> Subject: Re: double wound secondary (fwd)
> 
> Tesla list wrote:
> > ---------- Forwarded message ----------
> > Date: Sat, 29 Sep 2007 18:24:54 -0400
> > From: Scott Bogard <teslas-intern@xxxxxxxxxxx>
> > To: tesla@xxxxxxxxxx
> > Subject: double wound secondary
> >
> >
> > Hey everybody,
> >      I know, this topic has been covered an awful lot in the archives, I
> > looked; but there seems to be some disagreement, weather it is good or
> > bad.  It seems lately, everybody now thinks it is not such a bad idea, as
> > it decreases the resistance, therefore increasing output.  But, from what
> > I know of formulas and such, two inductors (since a coil is essentially an
> > inductor) in parallel decreases the inductance, which should decrease
> > voltage out?  Does this situation not apply with a transformer, or does
> > the resistance decrease make that much of a difference to make up for it?  
> > Or, does nobody actually know why it works so well?  Just curious (and
> > considering double winding my 6-in secondary). Scott Bogard.
> >
> > _________________________________________________________________
> Two coupled inductors in parallel, with bifilar winding and high coupling
> (M=sqrt(L1*L2)), act as a single inductor with L=L1=L2=M. The proof is 
> easy.
> It remains to be seen if the loss is smaller than when using a single wire
> with the same area of the two wires used in the bifilar winding.
> You can probably use a simulator as Javatc, that calculates wire losses,
> considering a single coil with the total number of turns with the two wires,
> and then divide the resulting resistance by 4 to obtain the resistance of
> the bifilar coil. Compare then with what happens with a wire with doubled
> area and single winding. In principle, I would expect similar results, or
> advantage for the single wire winding because there would be space between
> the turns, reducing the proximity effect, if the winding length is kept.
> Note that using the same winding length you can use a wire with twice the
> diameter, and so four times the area. The losses must be smaller in this
> case.
> 
> Antonio Carlos M. de Queiroz
> 
> 
> 

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