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Re: Tesla magnifiers (fwd)
---------- Forwarded message ----------
Date: Sun, 16 Sep 2007 16:09:59 +0000
From: jhowson4@xxxxxxxxxxx
To: Tesla list <tesla@xxxxxxxxxx>
Subject: Re: Tesla magnifiers (fwd)
ok thanks for the help I think I might just get it, but I am going to make
sure, So basically the inductance of the 2nd and 3rd coil along with the
self capacitance of the 2nd and 3rd coil and also the top-load give the
resonant frequency of the secondary side of the TC while the primary side
remains just like any other TC. So you want to think of it as a 2 coil
system instead of as a 3 coil system combining the 2nd and 3rd coil into 1
to do the math. Right?
Many Thanks,
Jay
-------------- Original message --------------
From: "Tesla list" <tesla@xxxxxxxxxx>
>
> ---------- Forwarded message ----------
> Date: Sun, 16 Sep 2007 11:59:18 -0300
> From: Antonio Carlos M. de Queiroz
> To: Tesla list
> Subject: Re: Tesla magnifiers (fwd)
>
> Tesla list wrote:
> > ---------- Forwarded message ----------
> > Date: Sat, 15 Sep 2007 21:33:29 +0000
> > From: jhowson4@xxxxxxxxxxx
> > To: tesla@xxxxxxxxxx
> > Subject: Tesla magnifiers
> >
> > Hello all I am researching about the tesla magnifier for an AP physics
> > paper at school and I read a bunch of sites about how it works and I am
> > still really confused. basically I think I understand that the primary
> > should be of a low inductance and should have a high coupling with the
> > secondary which should be of a slightly larger inductance, and that the
> > point of that is to generate a high voltage through normal transformer
> > action no resonance. This is where I am lost how is the resonant
> > frequency of the 3rd coil found.
> A magnifier with coils L1, L2, and L3, primary capacitor C1,
> tertiary capacitance C3, and coupling coefficient k12 between L1
> and L2 is equivalent to a two-coils system with:
> C1'=C1
> C2'=C3
> L1'=L1
> L2'=L2+L3
> k12'=k12*sqrt(L2/(L2+L3))
> This is easy to verify by using transformer equivalent circuits.
> The system can then be designed as a conventional coil, following
> the tuning relation:
> C1*L1=C3*(L2+L3)
> The inductances can be chosen as convenient.
> If k12' is high (>0.2), it's important to use one of the values of
> the coupling coefficient that result in complete energy transfer.
> This rarely happens in Tesla coils used for spark production, however.
>
> This works well as long as the capacitance C2 at the connection between
> L2 and L3 is negligible.
> If this capacitance is not negligible, it stores some energy that does
> not go to the output. C2 can be "tuned out" with somewhat more complex
> design formulas, that result in complete energy transfer from C1 to C3:
> http://www.coe.ufrj.br/~acmq/tesla/magnifier.html
>
> > Is it a sum of the secondary inductance
> > and the 3rd coil inductance with the capacitance of the top-load.
> This is the correct relation, kept in the simplified and ideal design
> formulas. Note that, as in a
> two-coils system, the capacitance of the topload includes the effect of
> the "self-capacitance" of
> the third coil, that approximately adds to it.
> > Or is
> > it just the 3rd coil and its top-load giving the resonant frequency. and
> > how is this frequency produced. Is the driver circuit frequency the same
> > as the resonant frequency of the 3rd coil and it is just having the
> > voltage increased by the secondary which is feeding the 3rd coil or what
> The driver resonance frequency is the resonance frequency of the
> combination L2+L3 and C3.
> The voltage that appears at the top of L2 is not related directly by
> "transformer action" to the other
> voltages, unless the coupling coefficient k12 is very high, what is
> usually not feasible.
> The magnifier is useful in energy conversion applications, because it
> allows very fast energy
> transfer without excessive proximity between the primary circuit and the
> output terminal. For
> spark production, the main advantage appears to be just the separation
> between the driver and
> the output coil. The system can be designed in a way that allows C2 to
> be just the distributed
> capacitance present at the connection between L2 and L3, but then the
> effect of C2 is already
> small, and the simplest approximation can be used.
>
> Antonio Carlos M. de Queiroz
>
>
>
>